What is the derivative of 8\sqrt[3]{x} ?

The derivative of 8\sqrt[3]{x} is 8/(3x^{2/3)}

What is the first derivative of 8\sqrt[3]{x} ?

The first derivative of 8\sqrt[3]{x} is 8/(3x^{2/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{8}{3 x ^{\frac{2}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 8 \frac{d}{d x} (x^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 \cdot \frac{1}{3} x^{\frac{1}{3} - 1}

Simplify

8 \cdot \frac{1}{3} x^{\frac{1}{3} - 1} : \frac{8}{3 x ^{\frac{2}{3}}}

= \frac{8}{3 x ^{\frac{2}{3}}}

\frac{d ^{2} y}{d x ^{2}} = \frac{1}{x} + 2

x \to - 2 lim (\frac{∣ x - 2 ∣}{x - 2})

\frac{\partial}{\partial x} ((x^{3} + y^{3})^{10})

\int \frac{5 - x ^{2}}{3 x ^{3} + x} d x

f (x) = x e^{3 x}

What is the derivative of 8\sqrt[3]{x} ?
The derivative of 8\sqrt[3]{x} is 8/(3x^{2/3)}
What is the first derivative of 8\sqrt[3]{x} ?
The first derivative of 8\sqrt[3]{x} is 8/(3x^{2/3)}