What is the integral from 1 to infinity of 5/(2x) ?

The integral from 1 to infinity of 5/(2x) is diverges

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integral from 1 to infinity of 5/(2x)

\int_{1}^{\infty} \frac{5}{2 x} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{5}{2 x} d x

Compute the indefinite integral:

\int \frac{5}{2 x} d x = \frac{5}{2} ln ∣ x ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{5}{2 x} d x =

diverges

= diverges

2 y y^{^{'}} + 3 - (y^{2} + 3) = 0, y (0) = 6

f (x) = \frac{3}{3 x + 4}

\int_{1}^{2} \frac{y + 5 y ^{7}}{y ^{3}} d y

\int x (x^{2} - 4) d x

n = 1 \sum \infty \frac{2}{n ln ( 7 n )}

What is the integral from 1 to infinity of 5/(2x) ?
The integral from 1 to infinity of 5/(2x) is diverges