What is area x=-2,x=3,y=x^2-12,y=x-6 ?

The answer to area x=-2,x=3,y=x^2-12,y=x-6 is 125/6

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area x=-2,x=3,y=x^2-12,y=x-6

area

x = - 2, x = 3, y = x^{2} - 12, y = x - 6

\frac{125}{6}

Decimal Notation

20.83333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{2} - 12 - (x - 6) d x

Solve

\int_{- 2}^{3} x^{2} - 12 - (x - 6) d x : \frac{125}{6}

The area is:

= \frac{125}{6}

1 - x^{12}

\frac{\partial ^{2}}{\partial x ^{2}} (\frac{1}{x y})

\int x sin (\frac{1}{6} x) d x

\int \frac{4}{x - 4} d x

\frac{156}{x}, - 49 x + 189

What is area x=-2,x=3,y=x^2-12,y=x-6 ?
The answer to area x=-2,x=3,y=x^2-12,y=x-6 is 125/6