What is the derivative of sin(e^x-1) ?

The derivative of sin(e^x-1) is cos(e^x-1)e^x

What is the first derivative of sin(e^x-1) ?

The first derivative of sin(e^x-1) is cos(e^x-1)e^x

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\frac{d}{d x} (sin (e^{x} - 1))

cos (e^{x} - 1) e^{x}

Solution steps

\frac{d}{d x} (sin (e^{x} - 1))

Apply the chain rule:

cos (e^{x} - 1) \frac{d}{d x} (e^{x} - 1)

= cos (e^{x} - 1) \frac{d}{d x} (e^{x} - 1)

\frac{d}{d x} (e^{x} - 1) = e^{x}

= cos (e^{x} - 1) e^{x}

4 x^{3} - 4 x^{2} + 3

n = 1 \sum \infty \frac{n ^{3}}{e ^{n}}

x \to 1 + lim (x^{\frac{8}{1 - x}})

x \to 0 - lim (∣ x ∣)

\frac{\partial}{\partial y} (e^{3 x} sin (3 y))

What is the derivative of sin(e^x-1) ?
The derivative of sin(e^x-1) is cos(e^x-1)e^x
What is the first derivative of sin(e^x-1) ?
The first derivative of sin(e^x-1) is cos(e^x-1)e^x