What is the tangent of 11-x^2(3.2) ?

The tangent of 11-x^2(3.2) is y=-6.4a_{0}x+(55+16a_{0}^2)/5

Popular >

tangent of 11-x^2(3.2)

tangent of

11 - x^{2} (3.2)

y = - 6.4 a_{0} x + \frac{55 + 16 a _{0}^{2}}{5}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 11 - a_{0}^{2} \cdot 3.2)

Find the slope of

y = 11 - x^{2} 3.2 : \frac{d y}{d x} = - 6.4 x

Compute the slope of

y = 11 - x^{2} 3.2

x = a_{0} : m = - 6.4 a_{0}

Find the line with slope m=

- 6.4 a_{0}

and passing through

(a_{0}, 11 - a_{0}^{2} 3.2) : y = - 6.4 a_{0} x + \frac{55 + 16 a _{0}^{2}}{5}

y = - 6.4 a_{0} x + \frac{55 + 16 a _{0}^{2}}{5}

\int tan^{4} (6 x) sec^{2} (6 x) d x

\frac{\partial}{\partial y} (y^{2} - 9)

\frac{d y}{d x} = - \frac{4 x + 4 y}{4 x + 9 y}

x \to 2 + lim (\frac{x - 3}{x ^{2} - 4})

\frac{\partial}{\partial y} (x^{4} + 8 x y^{7})

What is the tangent of 11-x^2(3.2) ?
The tangent of 11-x^2(3.2) is y=-6.4a_{0}x+(55+16a_{0}^2)/5