What is the solution for y^'=(xy^3)/(16) ?

The solution for y^'=(xy^3)/(16) is y=sqrt(-(16)/(x^2+c_{1))},y=-sqrt(-(16)/(x^2+c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(xy^3)/(16)

y^{^{'}} = \frac{x y ^{3}}{16}

y = - \frac{16}{x ^{2} + c _{1}}, y = - - \frac{16}{x ^{2} + c _{1}}

Solution steps

y^{'} (x) = \frac{x y ^{3}}{16}

Solve separable ODE:

y = - \frac{16}{x ^{2} + c _{1}}, y = - - \frac{16}{x ^{2} + c _{1}}

y = - \frac{16}{x ^{2} + c _{1}}, y = - - \frac{16}{x ^{2} + c _{1}}

\int x^{2} (4 - 2 x^{2}) d x

f (x) = x (x^{3} - x)

\frac{d}{d x} (\frac{6 x - 3}{5 x + 8})

\int \frac{4 x - 11}{2 x ^{2} - 11 x + 15} d x

\frac{\partial}{\partial y} (2 x + arctan (y^{2}))

What is the solution for y^'=(xy^3)/(16) ?
The solution for y^'=(xy^3)/(16) is y=sqrt(-(16)/(x^2+c_{1))},y=-sqrt(-(16)/(x^2+c_{1))}