What is the limit as x approaches-4 of (x^2)/(4x+16) ?

The limit as x approaches-4 of (x^2)/(4x+16) is diverges

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limit as x approaches-4 of (x^2)/(4x+16)

x \to - 4 lim (\frac{x ^{2}}{4 x + 16})

diverges

Solution steps

x \to - 4 lim (\frac{x ^{2}}{4 x + 16})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 4 + lim (\frac{x ^{2}}{4 x + 16}) = \infty

x \to - 4 - lim (\frac{x ^{2}}{4 x + 16}) = - \infty

= diverges

\int_{- \frac{1}{3}}^{\frac{1}{3}} \frac{1}{1 - x ^{2}} d x

\int sin (x^{\frac{1}{2}}) d x

\frac{\partial}{\partial y} (x ln (y))

x \frac{d y}{d x} + 3 y = x^{3} - x

What is the limit as x approaches-4 of (x^2)/(4x+16) ?
The limit as x approaches-4 of (x^2)/(4x+16) is diverges