What is the derivative of x^4-4x^2 ?

The derivative of x^4-4x^2 is 4x^3-8x

What is the first derivative of x^4-4x^2 ?

The first derivative of x^4-4x^2 is 4x^3-8x

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\frac{d}{d x} (x^{4} - 4 x^{2})

4 x^{3} - 8 x

Solution steps

\frac{d}{d x} (x^{4} - 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (4 x^{2}) = 8 x

= 4 x^{3} - 8 x

\frac{d y}{d t} + e^{t} y = 9 e^{t}

\frac{d y}{d x} = 6 y^{2} x

y = x^{2} - 5 x + 3, (2, - 3)

n = 5 \sum \infty 3 (0.9)^{n + 1}

x \to 0 lim (x - ln (x))

What is the derivative of x^4-4x^2 ?
The derivative of x^4-4x^2 is 4x^3-8x
What is the first derivative of x^4-4x^2 ?
The first derivative of x^4-4x^2 is 4x^3-8x