What is the derivative of-sec^2(x) ?

The derivative of-sec^2(x) is -2sec^2(x)tan(x)

What is the first derivative of-sec^2(x) ?

The first derivative of-sec^2(x) is -2sec^2(x)tan(x)

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derivative of

- sec^{2} (x)

- 2 sec^{2} (x) tan (x)

Solution steps

\frac{d}{d x} (- sec^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sec^{2} (x))

Apply the chain rule:

2 sec (x) \frac{d}{d x} (sec (x))

= 2 sec (x) \frac{d}{d x} (sec (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= - 2 sec (x) sec (x) tan (x)

Simplify

- 2 sec (x) sec (x) tan (x) : - 2 sec^{2} (x) tan (x)

= - 2 sec^{2} (x) tan (x)

\frac{d}{d n} (e^{niπ})

y^{^{''}} + y^{^{'}} + y = 0

\int (y^{5} + 5 y) d y

y^{^{''}} + y = 0, y (\frac{π}{3}) = 16, y^{^{'}} (\frac{π}{3}) = - 32

\frac{\partial}{\partial y} (7 e^{x^{2} l n (y)})

What is the derivative of-sec^2(x) ?
The derivative of-sec^2(x) is -2sec^2(x)tan(x)
What is the first derivative of-sec^2(x) ?
The first derivative of-sec^2(x) is -2sec^2(x)tan(x)