What is the sum from n=2 to infinity of 1/(n^2) ?

The sum from n=2 to infinity of 1/(n^2) is converges

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sum from n=2 to infinity of 1/(n^2)

n = 2 \sum \infty \frac{1}{n ^{2}}

converges

Solution steps

n = 2 \sum \infty \frac{1}{n ^{2}}

Apply p-Series Test:

converges

= converges

y = x^{- 4}

\int x^{3} - 5 x d x

e^{x y} + y = x - 1

\frac{x}{x ^{2} + 4}

\frac{\partial}{\partial x} (3 e^{x - y})

What is the sum from n=2 to infinity of 1/(n^2) ?
The sum from n=2 to infinity of 1/(n^2) is converges