What is the first derivative of 2x^2+6 ?

The first derivative of 2x^2+6 is 4x

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derivative of 2x^2+6

\frac{d}{d x} (2 x^{2} + 6)

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (6)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (6) = 0

= 4 x + 0

Simplify

= 4 x

x \to \infty lim (2 x - 3)

\frac{5}{x}, 4

n = 0 \sum \infty \frac{1}{e ^{5 n}}

\int (- 4 x^{3} + 2 e^{- 2 x} + \frac{1}{2 x}) d x

\frac{d y}{d x} + 4 (tan (4 x)) y = 10 cos (4 x)