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Popular >

(4pir^2)^'

Solution

(4 π r^{2})^{^{'}}

Solution

8 π r

Solution steps

(4 π r^{2})^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 π (r^{2})^{^{'}}

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 π 2 r^{2 - 1}

Simplify

= 8 π r

Popular Examples

derivative of (x-1^2(x-2)(x-4))

\frac{d}{d x} ((x - 1)^{2} (x - 2) (x - 4))

tangent of y=(2x)/((x^2+1))tangent of

y = \frac{2 x}{( x ^{2} + 1 )}

integral of 8/((4x^2+1)^2)

\int \frac{8}{( 4 x ^{2} + 1 ) ^{2}} d x

integral of (6-72x)/(sqrt(1-36x^2))

\int \frac{6 - 72 x}{1 - 36 x ^{2}} d x

derivative of (sqrt(x)/(x+2))

\frac{d}{d x} (\frac{x}{x + 2})

Frequently Asked Questions (FAQ)

What is the (4pir^2)^' ?
The (4pir^2)^' is 8pir
What is the first (4pir^2)^' ?
The first (4pir^2)^' is 8pir