What is the integral from 1 to 2 of 1/(x^8) ?

The integral from 1 to 2 of 1/(x^8) is 127/896

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integral from 1 to 2 of 1/(x^8)

\int_{1}^{2} \frac{1}{x ^{8}} d x

\frac{127}{896}

Decimal Notation

0.14174 \dots

Solution steps

\int_{1}^{2} \frac{1}{x ^{8}} d x

Apply the Power Rule

: [- \frac{1}{7 x ^{7}}]_{1}^{2}

= [- \frac{1}{7 x ^{7}}]_{1}^{2}

Compute the boundaries:

\frac{127}{896}

= \frac{127}{896}

n = 1 \sum \infty \frac{2}{( n + 2 ) ^{3}}

\frac{d}{d x} (e^{3 x - 3})

\frac{d}{d x} y = 5 x^{2} cos^{2} (y)

f (x) = 2 x cos (x), at x = \frac{3 π}{2}

\int 2 sin^{3} (x co) s^{5} x d x

What is the integral from 1 to 2 of 1/(x^8) ?
The integral from 1 to 2 of 1/(x^8) is 127/896