What is the integral of 1/(xln(2)) ?

The integral of 1/(xln(2)) is 1/(ln(2))ln|x|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(xln(2))

\int \frac{1}{x ln ( 2 )} d x

\frac{1}{ln ( 2 )} ln ∣ x ∣ + C

Solution steps

\int \frac{1}{x ln ( 2 )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{ln ( 2 )} \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{1}{ln ( 2 )} ln ∣ x ∣

Add a constant to the solution

= \frac{1}{ln ( 2 )} ln ∣ x ∣ + C

\frac{d}{d x} ((a x^{2} + b x + c) \cdot e^{- \frac{x}{4}})

x \to - \infty lim (1 + \frac{1}{x})

f (x) = x^{2} - 2 x

3 x, at x = 16

\int x \cdot sin (2 \cdot x) d x

What is the integral of 1/(xln(2)) ?
The integral of 1/(xln(2)) is 1/(ln(2))ln|x|+C