What is the solution for y^'=e^{4cos(sqrt(x))} ?

The solution for y^'=e^{4cos(sqrt(x))} is y=integral of e^{4cos(sqrt(x))}

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y^'=e^{4cos(sqrt(x))}

y^{^{'}} = e^{4 c o s (x)}

y = \int e^{4 c o s (x)} d x

Solution steps

y^{'} (x) = e^{4 c o s (x)}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int e^{4 c o s (x)} d x

y = \int e^{4 c o s (x)} d x

2

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2 x e^{- k x}

What is the solution for y^'=e^{4cos(sqrt(x))} ?
The solution for y^'=e^{4cos(sqrt(x))} is y=integral of e^{4cos(sqrt(x))}