What is the solution for (dy)/(dx)=(1+4y^2)(1+3x^2) ?

The solution for (dy)/(dx)=(1+4y^2)(1+3x^2) is y=(tan(2x+2x^3+c_{1}))/2

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(dy)/(dx)=(1+4y^2)(1+3x^2)

\frac{d y}{d x} = (1 + 4 y^{2}) (1 + 3 x^{2})

y = \frac{tan ( 2 x + 2 x ^{3} + c _{1} )}{2}

Solution steps

\frac{d y}{d x} = (1 + 4 y^{2}) (1 + 3 x^{2})

Solve separable ODE:

y = \frac{tan ( 2 x + 2 x ^{3} + c _{1} )}{2}

y = \frac{tan ( 2 x + 2 x ^{3} + c _{1} )}{2}

x \to 0 lim (\frac{sin ( 7 x )}{sin ( 9 x )})

\int 1 - tan^{2} (x) d x

(x^{3} + 4) e^{x}

f (x) = (1 - x) (x^{2} - 3) 2

x \to - 1 lim (x^{3})

What is the solution for (dy)/(dx)=(1+4y^2)(1+3x^2) ?
The solution for (dy)/(dx)=(1+4y^2)(1+3x^2) is y=(tan(2x+2x^3+c_{1}))/2