What is the tangent of y=5x-2x^2,(-2,-18) ?

The tangent of y=5x-2x^2,(-2,-18) is y=13x+8

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tangent of y=5x-2x^2,(-2,-18)

tangent of

y = 5 x - 2 x^{2}, (- 2, - 18)

y = 13 x + 8

Solution steps

Find the slope of

y = 5 x - 2 x^{2} : \frac{d y}{d x} = 5 - 4 x

Compute the slope of

y = 5 x - 2 x^{2}

(- 2, - 18) : m = 13

Find the line with slope m=

13

and passing through

(- 2, - 18) : y = 13 x + 8

y = 13 x + 8

\frac{d}{d x} (\frac{x + 7}{x - 7})

y = 3 x + 72, (3, 9)

y = \frac{7 x}{8}

x \to 0 lim (\frac{x ^{2}}{e ^{x} - 1})

\int 3 sec (x) d x

What is the tangent of y=5x-2x^2,(-2,-18) ?
The tangent of y=5x-2x^2,(-2,-18) is y=13x+8