What is the limit as x approaches 7-of (2x+1)/(x-7) ?

The limit as x approaches 7-of (2x+1)/(x-7) is -infinity

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limit as x approaches 7-of (2x+1)/(x-7)

x \to 7 - lim (\frac{2 x + 1}{x - 7})

- \infty

Solution steps

x \to 7 - lim (\frac{2 x + 1}{x - 7})

\frac{2 x + 1}{x - 7} = (2 x + 1) \frac{1}{x - 7}

= x \to 7 - lim ((2 x + 1) \frac{1}{x - 7})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 7 - lim (2 x + 1) \cdot x \to 7 - lim (\frac{1}{x - 7})

x \to 7 - lim (2 x + 1) = 15

x \to 7 - lim (\frac{1}{x - 7}) = - \infty

= 15 (- \infty)

Apply Infinity Property:

c \cdot (- \infty) = - \infty

= - \infty

x \to \infty lim (1.0 7^{x})

3 sin (t) - 3 cos (t)

f (x) = \frac{4 + x}{x - 2}, at x = 8

x y y^{^{'}} = x^{2} + 3 y^{2}

3 x, x 64 - x^{2}

What is the limit as x approaches 7-of (2x+1)/(x-7) ?
The limit as x approaches 7-of (2x+1)/(x-7) is -infinity