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Popular >

y^'=e(-2t)-y

Solution

y^{^{'}} = e (- 2 t) - y

Solution

y = - 2 e (t - 1) + \frac{c _{1}}{e ^{t}}

Solution steps

y^{'} (t) = e (- 2 t) - y

Solve linear ODE:

y = - 2 e (t - 1) + \frac{c _{1}}{e ^{t}}

y = - 2 e (t - 1) + \frac{c _{1}}{e ^{t}}

Popular Examples

derivative of f(x)=(x^3+5x^2-3)sqrt(x)derivative of

f (x) = (x^{3} + 5 x^{2} - 3) x

(cos (3 x))^{^{'}}

derivative of e^x-1-x

\frac{d}{d x} (e^{x} - 1 - x)

(dy)/(dx)=e^{-x^2}

\frac{d y}{d x} = e^{- x^{2}}

integral of sech^6(x)tanh(x)

\int sech^{6} (x) tanh (x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=e(-2t)-y ?
The solution for y^'=e(-2t)-y is y=-2e(t-1)+(c_{1})/(e^t)