What is the solution for (dP)/(dt)=kP^{1.01},P(0)=10 ?

The solution for (dP)/(dt)=kP^{1.01},P(0)=10 is P=(100^{100})/((kt-2^{1.99)*5^{1.99})^{100}}

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(dP)/(dt)=kP^{1.01},P(0)=10

\frac{d P}{d t} = k P^{1.01}, P (0) = 10

P = \frac{10 0 ^{100}}{( k t - 2 ^{1.99} \cdot 5 ^{1.99} ) ^{100}}

Solution steps

\frac{d P}{d t} = k P^{1.01}

Solve separable ODE:

P = \frac{10 0 ^{100}}{( k t - 2 ^{1.99} \cdot 5 ^{1.99} ) ^{100}}

P = \frac{10 0 ^{100}}{( k t - 2 ^{1.99} \cdot 5 ^{1.99} ) ^{100}}

y^{^{''}} + 2 y^{^{'}} + 5 y = 6 sin (2 t)

\frac{d ^{2}}{d x ^{2}} (cos (5 x))

x \to 0 lim (\frac{a ^{x} - b ^{x}}{x})

y = 2 x^{2}, (- 2, 8)

\int_{0}^{5} (t^{2} + 2 t - 15) d t

What is the solution for (dP)/(dt)=kP^{1.01},P(0)=10 ?
The solution for (dP)/(dt)=kP^{1.01},P(0)=10 is P=(100^{100})/((kt-2^{1.99)*5^{1.99})^{100}}