What is the integral of (-1)/(sqrt(1-x^2)) ?

The integral of (-1)/(sqrt(1-x^2)) is -arcsin(x)+C

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integral of (-1)/(sqrt(1-x^2))

\int \frac{- 1}{1 - x ^{2}} d x

- arcsin (x) + C

Solution steps

\int \frac{- 1}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= - arcsin (x)

Add a constant to the solution

= - arcsin (x) + C

\frac{d}{d x} (\frac{1 + x}{x})

\frac{d}{d x} ((a - \frac{b}{x})^{2})

\frac{2.4}{5 + 1 x}

\int \frac{x}{4 - x} d x

y = ln (ln (8 x))

What is the integral of (-1)/(sqrt(1-x^2)) ?
The integral of (-1)/(sqrt(1-x^2)) is -arcsin(x)+C