What is the derivative of (x^4/5) ?

The derivative of (x^4/5) is (4x^3)/5

What is the first derivative of (x^4/5) ?

The first derivative of (x^4/5) is (4x^3)/5

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\frac{d}{d x} (\frac{x ^{4}}{5})

\frac{4 x ^{3}}{5}

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{5} \cdot 4 x^{4 - 1}

Simplify

\frac{1}{5} \cdot 4 x^{4 - 1} : \frac{4 x ^{3}}{5}

= \frac{4 x ^{3}}{5}

f (x) = - x^{3} - 3 x^{2} - 3, at x = - 3

x \to - 1 lim (\frac{x + 2}{x ^{2} + x})

\int (2.286 x - 2.5 (x - 3) - 3 (x - 5)) d x

- 6 e^{- x^{2}} x

\int \frac{1}{x} d x

What is the derivative of (x^4/5) ?
The derivative of (x^4/5) is (4x^3)/5
What is the first derivative of (x^4/5) ?
The first derivative of (x^4/5) is (4x^3)/5