What is the derivative of y=tan(pix) ?

The derivative of y=tan(pix) is sec^2(pix)pi

What is the first derivative of y=tan(pix) ?

The first derivative of y=tan(pix) is sec^2(pix)pi

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derivative of

y = tan (π x)

sec^{2} (π x) π

Solution steps

\frac{d}{d x} (tan (π x))

Apply the chain rule:

sec^{2} (π x) \frac{d}{d x} (π x)

= sec^{2} (π x) \frac{d}{d x} (π x)

\frac{d}{d x} (π x) = π

= sec^{2} (π x) π

\frac{d}{d x} (2 x e^{2 y} - x cos (x y) + 2 y)

x \to - 2 lim (6 - 3 x - 3)

\int \frac{x ^{3}}{x ln ( x )} d x

x \to 0 + lim (e^{\frac{1}{x}})

\int e^{- 3 t} d t

What is the derivative of y=tan(pix) ?
The derivative of y=tan(pix) is sec^2(pix)pi
What is the first derivative of y=tan(pix) ?
The first derivative of y=tan(pix) is sec^2(pix)pi