What is the derivative of y=2x^2+1 ?

The derivative of y=2x^2+1 is 4x

What is the first derivative of y=2x^2+1 ?

The first derivative of y=2x^2+1 is 4x

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derivative of

y = 2 x^{2} + 1

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (1) = 0

= 4 x + 0

Simplify

= 4 x

\frac{d}{d x} (\frac{( x + 1 ) ^{3}}{3} + \frac{1}{4 x + 4})

3 x^{2} e^{x}

\int 2 sin (x) + x d x

\frac{d}{d x} (5 x + \frac{3}{x})

x \to 0 lim (sin (x) ln (3 x))

What is the derivative of y=2x^2+1 ?
The derivative of y=2x^2+1 is 4x
What is the first derivative of y=2x^2+1 ?
The first derivative of y=2x^2+1 is 4x