What is the solution for cos(x)y^'+sin(x)y=1 ?

The solution for cos(x)y^'+sin(x)y=1 is y=(tan(x))/(sec(x))+(c_{1})/(sec(x))

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cos(x)y^'+sin(x)y=1

cos (x) y^{^{'}} + sin (x) y = 1

y = \frac{tan ( x )}{sec ( x )} + \frac{c _{1}}{sec ( x )}

Solution steps

cos (x) y^{'} (x) + sin (x) y = 1

Solve linear ODE:

y = \frac{tan ( x )}{sec ( x )} + \frac{c _{1}}{sec ( x )}

y = \frac{tan ( x )}{sec ( x )} + \frac{c _{1}}{sec ( x )}

\int \frac{2 x + 3}{x + 2} d x

\frac{d}{d x} (sin (x^{2}) cos (π x + 2))

\frac{\partial}{\partial y} (4 x^{3} - 36 x)

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(1999, 67%), (2005, 92%)

What is the solution for cos(x)y^'+sin(x)y=1 ?
The solution for cos(x)y^'+sin(x)y=1 is y=(tan(x))/(sec(x))+(c_{1})/(sec(x))