What is the integral of 5\sqrt[3]{x} ?

The integral of 5\sqrt[3]{x} is 15/4 x^{4/3}+C

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integral of 5\sqrt[3]{x}

\frac{15}{4} x^{\frac{4}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= 5 \cdot \frac{3}{4} x^{\frac{4}{3}}

Simplify

5 \cdot \frac{3}{4} x^{\frac{4}{3}} : \frac{15}{4} x^{\frac{4}{3}}

= \frac{15}{4} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{15}{4} x^{\frac{4}{3}} + C

y^{^{''}} - 9 y^{^{'}} + 9 y = 0

n = 1 \sum \infty \frac{2}{n + 7}

y = 6 x, y = 2 x^{2}

\frac{d}{d x} (sin^{3} (5 x^{2}))

\int \frac{1}{5 x ^{3}} d x

What is the integral of 5\sqrt[3]{x} ?
The integral of 5\sqrt[3]{x} is 15/4 x^{4/3}+C