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Popular >

integral from 1 to 2 of 2x^3-4

Solution

\int_{1}^{2} 2 x^{3} - 4 d x

Solution

\frac{7}{2}

+1

Decimal Notation

3.5

Solution steps

\int_{1}^{2} 2 x^{3} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x^{3} d x - \int_{1}^{2} 4 d x

\int_{1}^{2} 2 x^{3} d x = \frac{15}{2}

\int_{1}^{2} 4 d x = 4

= \frac{15}{2} - 4

Simplify

\frac{15}{2} - 4 : \frac{7}{2}

= \frac{7}{2}

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\frac{2 s}{( s ^{2} + 4 ) ^{2}}

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\frac{d}{d x} (\frac{x + 1}{x})

limit as t approaches infinity of 1/t

t \to \infty lim (\frac{1}{t})

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\int \frac{18}{x ^{2} + 1} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of 2x^3-4 ?
The integral from 1 to 2 of 2x^3-4 is 7/2