What is the derivative of 2^{2x} ?

The derivative of 2^{2x} is ln(2)*2^{2x+1}

What is the first derivative of 2^{2x} ?

The first derivative of 2^{2x} is ln(2)*2^{2x+1}

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derivative of

2^{2 x}

ln (2) \cdot 2^{2 x + 1}

Solution steps

\frac{d}{d x} (2^{2 x})

Simplify

2^{2 x} : 4^{x}

= \frac{d}{d x} (4^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4^{x} ln (4)

Simplify

4^{x} ln (4) : ln (2) \cdot 2^{2 x + 1}

= ln (2) \cdot 2^{2 x + 1}

\int x 4 x^{2} + 1 d x

\frac{d}{d x} (e^{5 x - 4 x^{2}})

\frac{d}{d x} (\frac{x}{7 x + 1})

1 - x^{2}, x - 1

\int \frac{1}{x ln ( 10 )} d x

What is the derivative of 2^{2x} ?
The derivative of 2^{2x} is ln(2)*2^{2x+1}
What is the first derivative of 2^{2x} ?
The first derivative of 2^{2x} is ln(2)*2^{2x+1}