What is the integral from 1 to 5 of sqrt(1+2^2) ?

The integral from 1 to 5 of sqrt(1+2^2) is 4sqrt(5)

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integral from 1 to 5 of sqrt(1+2^2)

\int_{1}^{5} 1 + 2^{2} d x

45

Decimal Notation

8.94427 \dots

Solution steps

\int_{1}^{5} 1 + 2^{2} d x

Integral of a constant:

\int a d x = a x

= [1 + 2^{2} x]_{1}^{5}

Simplify

= [5 x]_{1}^{5}

Compute the boundaries:

45

= 45

x \to \infty lim (\frac{1}{9})

7^{^{'}}

y^{^{''}} + y = (t^{2} + t) sin (t)

\frac{d y}{d x}, x y = 18

f (t) = \frac{4 t + 8}{t + 3}

What is the integral from 1 to 5 of sqrt(1+2^2) ?
The integral from 1 to 5 of sqrt(1+2^2) is 4sqrt(5)