What is the limit as t approaches 0 of sin(4t) ?

The limit as t approaches 0 of sin(4t) is 0

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limit as t approaches 0 of sin(4t)

t \to 0 lim (sin (4 t))

0

Solution steps

t \to 0 lim (sin (4 t))

Plug in the value

t = 0

= sin (4 \cdot 0)

Simplify

sin (4 \cdot 0) : 0

= 0

\frac{d}{d x} ((x - y + 2)^{2})

\frac{\partial}{\partial z} (x^{2} y^{4} + z^{3})

\int \frac{x}{x ^{2} - 4} d x

\frac{cos ( 2 x )}{3}

y^{^{'}} - t y^{3} = 0, y (0) = 2

What is the limit as t approaches 0 of sin(4t) ?
The limit as t approaches 0 of sin(4t) is 0