What is the derivative of 14x(x^2+4)^6 ?

The derivative of 14x(x^2+4)^6 is 14((x^2+4)^6+12x^2(x^2+4)^5)

What is the first derivative of 14x(x^2+4)^6 ?

The first derivative of 14x(x^2+4)^6 is 14((x^2+4)^6+12x^2(x^2+4)^5)

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derivative of

14 x (x^{2} + 4)^{6}

14 ((x^{2} + 4)^{6} + 12 x^{2} (x^{2} + 4)^{5})

Solution steps

\frac{d}{d x} (14 x (x^{2} + 4)^{6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 14 \frac{d}{d x} (x (x^{2} + 4)^{6})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = (x^{2} + 4)^{6}

= 14 (\frac{d x}{d x} (x^{2} + 4)^{6} + \frac{d}{d x} ((x^{2} + 4)^{6}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} + 4)^{6}) = 12 x (x^{2} + 4)^{5}

= 14 (1 \cdot (x^{2} + 4)^{6} + 12 x (x^{2} + 4)^{5} x)

Simplify

14 (1 \cdot (x^{2} + 4)^{6} + 12 x (x^{2} + 4)^{5} x) : 14 ((x^{2} + 4)^{6} + 12 x^{2} (x^{2} + 4)^{5})

= 14 ((x^{2} + 4)^{6} + 12 x^{2} (x^{2} + 4)^{5})

5 x^{2} cos (x) cot (x)

y^{^{''}} = 9 t^{2}

\int cos (n) π x d x

\int (π - x) d x

What is the derivative of 14x(x^2+4)^6 ?
The derivative of 14x(x^2+4)^6 is 14((x^2+4)^6+12x^2(x^2+4)^5)
What is the first derivative of 14x(x^2+4)^6 ?
The first derivative of 14x(x^2+4)^6 is 14((x^2+4)^6+12x^2(x^2+4)^5)