What is the integral of \sqrt[13]{x^3} ?

The integral of \sqrt[13]{x^3} is 13/16 x^{16/13}+C

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integral of \sqrt[13]{x^3}

\frac{13}{16} x^{\frac{16}{13}} + C

Solution steps

assuming

x \geq 0

= \int x^{\frac{3}{13}} d x

Apply the Power Rule

: \frac{13}{16} x^{\frac{16}{13}}

= \frac{13}{16} x^{\frac{16}{13}}

Add a constant to the solution

= \frac{13}{16} x^{\frac{16}{13}} + C

14 t - sin (7 t)

\int (e^{x} cos (x)) d x

x \to 2 lim (x (x - 1))

x, 2

What is the integral of \sqrt[13]{x^3} ?
The integral of \sqrt[13]{x^3} is 13/16 x^{16/13}+C