What is the derivative of-(x^3+x-1/2) ?

The derivative of-(x^3+x-1/2) is -1/2 (3x^2+1)

What is the first derivative of-(x^3+x-1/2) ?

The first derivative of-(x^3+x-1/2) is -1/2 (3x^2+1)

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Popular >

\frac{d}{d x} (- \frac{x ^{3} + x - 1}{2})

- \frac{1}{2} (3 x^{2} + 1)

Solution steps

\frac{d}{d x} (- \frac{x ^{3} + x - 1}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{2} \frac{d}{d x} (x^{3} + x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{1}{2} (\frac{d}{d x} (x^{3}) + \frac{d x}{d x} - \frac{d}{d x} (1))

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= - \frac{1}{2} (3 x^{2} + 1 - 0)

Simplify

= - \frac{1}{2} (3 x^{2} + 1)

\frac{10}{( s ( s + 1 ) )}

sin^{2} (y) d x + x sin (2 y) d y = 0

\int sin^{3} (7 x) d x

\int 8 e^{4 x} d x

y = 6 x

What is the derivative of-(x^3+x-1/2) ?
The derivative of-(x^3+x-1/2) is -1/2 (3x^2+1)
What is the first derivative of-(x^3+x-1/2) ?
The first derivative of-(x^3+x-1/2) is -1/2 (3x^2+1)