What is the derivative of sqrt(20+x) ?

The derivative of sqrt(20+x) is 1/(2sqrt(20+x))

What is the first derivative of sqrt(20+x) ?

The first derivative of sqrt(20+x) is 1/(2sqrt(20+x))

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\frac{d}{d x} (20 + x)

\frac{1}{2 20 + x}

Solution steps

\frac{d}{d x} (20 + x)

Apply the chain rule:

\frac{1}{2 20 + x} \frac{d}{d x} (20 + x)

= \frac{1}{2 20 + x} \frac{d}{d x} (20 + x)

\frac{d}{d x} (20 + x) = 1

= \frac{1}{2 20 + x} \cdot 1

Simplify

= \frac{1}{2 20 + x}

\frac{\partial}{\partial x} ((x y - 3) e^{- x y})

y^{^{''}} - 4 y^{^{'}} + 3 y = 3 x^{2} - 5 x + 1

\int \frac{4 x ^{2} + 2}{1 + x ^{2}} d x

\int_{1}^{5} \frac{3}{x ^{2}} d x

x^{2} y^{^{''}} - 4 x y^{^{'}} + 6 y = 0

What is the derivative of sqrt(20+x) ?
The derivative of sqrt(20+x) is 1/(2sqrt(20+x))
What is the first derivative of sqrt(20+x) ?
The first derivative of sqrt(20+x) is 1/(2sqrt(20+x))