What is the limit as n approaches infinity of \sum_{i=3}^8(i+1)^2 ?

The limit as n approaches infinity of \sum_{i=3}^8(i+1)^2 is 327

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limit as n approaches infinity of \sum_{i=3}^8(i+1)^2

n \to \infty lim (i = 3 \sum 8 (i + 1)^{2})

327

Solution steps

n \to \infty lim (i = 3 \sum 8 (i + 1)^{2})

i = 3 \sum 8 (i + 1)^{2} = 327

= n \to \infty lim (327)

n \to \infty lim (327) = 327

= 327

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What is the limit as n approaches infinity of \sum_{i=3}^8(i+1)^2 ?
The limit as n approaches infinity of \sum_{i=3}^8(i+1)^2 is 327