What is the limit as x approaches 1 of 4/(x^2-1) ?

The limit as x approaches 1 of 4/(x^2-1) is diverges

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limit as x approaches 1 of 4/(x^2-1)

x \to 1 lim (\frac{4}{x ^{2} - 1})

diverges

Solution steps

x \to 1 lim (\frac{4}{x ^{2} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{4}{x ^{2} - 1}) = \infty

x \to 1 - lim (\frac{4}{x ^{2} - 1}) = - \infty

= diverges

\frac{d}{d x} ((3 x + 1)^{4})

\frac{d}{d x} (cos (y) \frac{d y}{d x})

5 x^{- 4}

\int (x + 1) \cdot (x - x + 1) d x

e^{x + y} d x + d y = 0

What is the limit as x approaches 1 of 4/(x^2-1) ?
The limit as x approaches 1 of 4/(x^2-1) is diverges