What is the derivative of 3x^2+3x ?

The derivative of 3x^2+3x is 6x+3

What is the first derivative of 3x^2+3x ?

The first derivative of 3x^2+3x is 6x+3

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derivative of

3 x^{2} + 3 x

6 x + 3

Solution steps

\frac{d}{d x} (3 x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3 x) = 3

= 6 x + 3

\frac{d}{d x} (2 ln (x) - \frac{x ^{2}}{16})

\int \frac{x}{9 x ^{2} - 4} d x

y^{^{''}} + 6 y^{^{'}} + 34 y = 68, y (0) = 5, y^{^{'}} (0) = 7

\int x^{0.813} d x

x y + y^{^{'}} = 18 x

What is the derivative of 3x^2+3x ?
The derivative of 3x^2+3x is 6x+3
What is the first derivative of 3x^2+3x ?
The first derivative of 3x^2+3x is 6x+3