What is the integral of (2x-2)e^{-x} ?

The integral of (2x-2)e^{-x} is -2e^{-x}x+C

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integral of (2x-2)e^{-x}

\int (2 x - 2) e^{- x} d x

- 2 e^{- x} x + C

Solution steps

\int (2 x - 2) e^{- x} d x

Apply Integration By Parts

: - e^{- x} (2 x - 2) - \int - 2 e^{- x} d x

= - e^{- x} (2 x - 2) - \int - 2 e^{- x} d x

\int - 2 e^{- x} d x = 2 e^{- x}

= - e^{- x} (2 x - 2) - 2 e^{- x}

Simplify

- e^{- x} (2 x - 2) - 2 e^{- x} : - 2 e^{- x} x

= - 2 e^{- x} x

Add a constant to the solution

= - 2 e^{- x} x + C

\frac{d}{d x} (5 x^{7} e^{x})

y^{^{'}} = 5 x + y, y (0) = 6

\int l x d x

x^{l n (3)}

\int \frac{3 x - 18}{( x - 9 ) ( x - 5 ) ^{2}} d x

What is the integral of (2x-2)e^{-x} ?
The integral of (2x-2)e^{-x} is -2e^{-x}x+C