What is the slope of y=(4x+1)^2,(0,1) ?

The slope of y=(4x+1)^2,(0,1) is 8

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slope of y=(4x+1)^2,(0,1)

slope

y = (4 x + 1)^{2}, (0, 1)

8

Solution steps

y = (4 x + 1)^{2}

In order to find the slope of the function, take the derivative of

(4 x + 1)^{2}

\frac{d}{d x} ((4 x + 1)^{2}) = 8 (4 x + 1)

8 (4 x + 1)

Find the value of

8 (4 x + 1)

for

x = 0 : 8

8

f (- 8) = 6 (1 - x)

x \to 1 - lim (\frac{x - 2}{x - 1})

\frac{d}{d x} (ln (\frac{x - 1}{x + 2}))

\int_{- 3}^{5} 4 d x

f (x) = 4^{s i n (2) (x) + c o s (3 x)}