What is the tangent of f(x)=x^2+8,(4,24) ?

The tangent of f(x)=x^2+8,(4,24) is y=8x-8

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tangent of f(x)=x^2+8,(4,24)

tangent of

f (x) = x^{2} + 8, (4, 24)

y = 8 x - 8

Solution steps

Find the slope of

f (x) = x^{2} + 8 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} + 8

(4, 24) : m = 8

Find the line with slope m=

8

and passing through

(4, 24) : y = 8 x - 8

y = 8 x - 8

\frac{d}{d x} (\frac{3 - 2 x}{3 + 2 x})

\int x^{4} sin (3 x) d x

\int - (x^{2} + 2) e^{x} d x

\frac{\partial}{\partial x} (3^{2 y})

f (x) = 2^{70}

What is the tangent of f(x)=x^2+8,(4,24) ?
The tangent of f(x)=x^2+8,(4,24) is y=8x-8