What is the integral of x^{1.1}+7x^{2.5} ?

The integral of x^{1.1}+7x^{2.5} is 0.47619…x^{2.1}+2x^{3.5}+C

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integral of x^{1.1}+7x^{2.5}

\int x^{1.1} + 7 x^{2.5} d x

0.47619 \dots x^{2.1} + 2 x^{3.5} + C

Solution steps

\int x^{1.1} + 7 x^{2.5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{1.1} d x + \int 7 x^{2.5} d x

\int x^{1.1} d x = 0.47619 \dots x^{2.1}

\int 7 x^{2.5} d x = 2 x^{3.5}

= 0.47619 \dots x^{2.1} + 2 x^{3.5}

Add a constant to the solution

= 0.47619 \dots x^{2.1} + 2 x^{3.5} + C

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What is the integral of x^{1.1}+7x^{2.5} ?
The integral of x^{1.1}+7x^{2.5} is 0.47619…x^{2.1}+2x^{3.5}+C