What is the solution for (dy)/(dx)=((x-4))/((y-6)) ?

The solution for (dy)/(dx)=((x-4))/((y-6)) is y=6+sqrt(x^2-8x+c_{1)+36},y=6-sqrt(x^2-8x+c_{1)+36}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=((x-4))/((y-6))

\frac{d y}{d x} = \frac{( x - 4 )}{( y - 6 )}

y = 6 + x^{2} - 8 x + c_{1} + 36, y = 6 - x^{2} - 8 x + c_{1} + 36

Solution steps

\frac{d y}{d x} = \frac{( x - 4 )}{( y - 6 )}

Solve separable ODE:

y = 6 + x^{2} - 8 x + c_{1} + 36, y = 6 - x^{2} - 8 x + c_{1} + 36

y = 6 + x^{2} - 8 x + c_{1} + 36, y = 6 - x^{2} - 8 x + c_{1} + 36

\frac{\partial}{\partial x} (x y e^{(- 5 y)})

\int \frac{cos ( x )}{sin ( x ) - cos ( x )} d x

\int \frac{1}{2 x} d x

\int_{1}^{4} \frac{1}{( x - 2 ) ^{\frac{1}{3}}} d x

\frac{d}{d x} (1 0^{- x})

What is the solution for (dy)/(dx)=((x-4))/((y-6)) ?
The solution for (dy)/(dx)=((x-4))/((y-6)) is y=6+sqrt(x^2-8x+c_{1)+36},y=6-sqrt(x^2-8x+c_{1)+36}