What is area y=-x+4,y=(x^2)/3 ?

The answer to area y=-x+4,y=(x^2)/3 is 4sqrt(57)-(5sqrt(19))/(2sqrt(3))

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area y=-x+4,y=(x^2)/3

area

y = - x + 4, y = \frac{x ^{2}}{3}

457 - \frac{5 19}{2 3}

Decimal Notation

23.90780 \dots

Solution steps

Apply the area formula:

\int_{\frac{- 3 - 57}{2}}^{\frac{- 3 + 57}{2}} - x + 4 - \frac{x ^{2}}{3} d x

Solve

\int_{\frac{- 3 - 57}{2}}^{\frac{- 3 + 57}{2}} - x + 4 - \frac{x ^{2}}{3} d x : 457 - \frac{5 19}{2 3}

The area is:

= 457 - \frac{5 19}{2 3}

\frac{d}{d x} (csc^{2} (x) - 4)

\frac{4}{x ^{2} + x}

e^{- x}, 0

\frac{d}{d x} ((2 x + 5) (3 x^{2} - 4 x + 1))

(x + 1) (ln (x + 1))

What is area y=-x+4,y=(x^2)/3 ?
The answer to area y=-x+4,y=(x^2)/3 is 4sqrt(57)-(5sqrt(19))/(2sqrt(3))