What is area e^{2x},e^{5x},x=1 ?

The answer to area e^{2x},e^{5x},x=1 is (2e^5-5e^2+3)/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area e^{2x},e^{5x},x=1

area

e^{2 x}, e^{5 x}, x = 1

\frac{2 e ^{5} - 5 e ^{2} + 3}{10}

Decimal Notation

26.28810 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} e^{2 x} - e^{5 x} d x

Solve

\int_{0}^{1} e^{2 x} - e^{5 x} d x : \frac{2 e ^{5} - 5 e ^{2} + 3}{10}

The area is:

= \frac{2 e ^{5} - 5 e ^{2} + 3}{10}

\frac{\partial}{\partial x} (x 1 + y^{9})

\frac{\partial}{\partial x} (5 e^{- x} cos (y))

\frac{d}{d x} (\frac{1}{1 + 4 x ^{2} + 9 x ^{4}})

\frac{d}{d θ} (2 - 2 sin (θ))

What is area e^{2x},e^{5x},x=1 ?
The answer to area e^{2x},e^{5x},x=1 is (2e^5-5e^2+3)/(10)