What is the tangent of y=3x^3-x^2+7,(2,27) ?

The tangent of y=3x^3-x^2+7,(2,27) is y=32x-37

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=3x^3-x^2+7,(2,27)

tangent of

y = 3 x^{3} - x^{2} + 7, (2, 27)

y = 32 x - 37

Solution steps

Find the slope of

y = 3 x^{3} - x^{2} + 7 : \frac{d y}{d x} = 9 x^{2} - 2 x

Compute the slope of

y = 3 x^{3} - x^{2} + 7

(2, 27) : m = 32

Find the line with slope m=

32

and passing through

(2, 27) : y = 32 x - 37

y = 32 x - 37

\int (x + 4) (x + 2) d x

\int (4 x^{2}) d x

y = 13 x, y = x^{2}

\int \frac{( 2 + x + x )}{x} d x

\int \frac{1}{7 ( x ^{2} + 1 )} d x

What is the tangent of y=3x^3-x^2+7,(2,27) ?
The tangent of y=3x^3-x^2+7,(2,27) is y=32x-37