What is the solution for y^'+xy=4xy^{7/2} ?

The solution for y^'+xy=4xy^{7/2} is y= 1/((e^{(5x^2-c_{1))/4}+4)^{2/5}}

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y^'+xy=4xy^{7/2}

y^{^{'}} + x y = 4 x y^{\frac{7}{2}}

y = \frac{1}{( e ^{\frac{5 x ^{2} - c _{1}}{4}} + 4 ) ^{\frac{2}{5}}}

Solution steps

y^{'} (x) + x y = 4 x y^{\frac{7}{2}}

Solve Bernoulli ODE:

y = \frac{1}{( e ^{\frac{5 x ^{2} - c _{1}}{4}} + 4 ) ^{\frac{2}{5}}}

y = \frac{1}{( e ^{\frac{5 x ^{2} - c _{1}}{4}} + 4 ) ^{\frac{2}{5}}}

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What is the solution for y^'+xy=4xy^{7/2} ?
The solution for y^'+xy=4xy^{7/2} is y= 1/((e^{(5x^2-c_{1))/4}+4)^{2/5}}