What is the tangent of-x^2+4sqrt(x),\at x=4 ?

The tangent of-x^2+4sqrt(x),\at x=4 is y=-7x+20

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tangent of-x^2+4sqrt(x),\at x=4

tangent of

- x^{2} + 4 x, at x = 4

y = - 7 x + 20

Solution steps

Find the tangent point:

(4, - 8)

Find the slope of

y = - x^{2} + 4 x : \frac{d y}{d x} = - 2 x + \frac{2}{x}

Compute the slope of

y = - x^{2} + 4 x

x = 4 : m = - 7

Find the line with slope m=

- 7

and passing through

(4, - 8) : y = - 7 x + 20

y = - 7 x + 20

\int x + y + 1 d x

y^{^{'}} = 7 x + y, y (0) = 5

\int \frac{1}{x ^{2} - 2 x} d x

3 x^{2}, (1, 3)

\int_{0}^{π} 12 sin^{4} (x) d x

What is the tangent of-x^2+4sqrt(x),\at x=4 ?
The tangent of-x^2+4sqrt(x),\at x=4 is y=-7x+20