What is the solution for (-19xy^2+10y)+(-19x^2y+10x)y^'=0 ?

The solution for (-19xy^2+10y)+(-19x^2y+10x)y^'=0 is y=(c_{1})/x

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(-19xy^2+10y)+(-19x^2y+10x)y^'=0

(- 19 x y^{2} + 10 y) + (- 19 x^{2} y + 10 x) y^{^{'}} = 0

y = \frac{c _{1}}{x}

Solution steps

(- 19 x y^{2} + 10 y) + (- 19 x^{2} y + 10 x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

x^{2} y \frac{d y}{d x} = e^{y}

x \to 2 - lim (\frac{x - 2}{∣ x - 2 ∣})

y^{^{'}} = \frac{( 3 x ^{2} - e ^{x} )}{2 y - 5}

y^{^{''}} + 11 y^{^{'}} + 30 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\int_{1}^{4} 3 x e^{x} d x

What is the solution for (-19xy^2+10y)+(-19x^2y+10x)y^'=0 ?
The solution for (-19xy^2+10y)+(-19x^2y+10x)y^'=0 is y=(c_{1})/x