What is the limit as x approaches+x of (x^2-1)/(x-1) ?

The limit as x approaches+x of (x^2-1)/(x-1) is x+1

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limit as x approaches+x of (x^2-1)/(x-1)

x \to + x lim (\frac{x ^{2} - 1}{x - 1})

x + 1

Solution steps

x \to x lim (\frac{x ^{2} - 1}{x - 1})

x \to x lim [f (x)] = f (x)

= \frac{x ^{2} - 1}{x - 1}

Simplify

\frac{x ^{2} - 1}{x - 1} : x + 1

= x + 1

f (x) = \frac{7}{( x ^{2} - 10 ) ^{4}}

f (x) = \frac{4}{x} - 16 sec (x)

\frac{d}{d x} (6 e^{- \frac{x}{2}})

\int - 3 x^{4} - 6 x^{2} + 8 d x

x \to 0 lim (x csc (π x))

What is the limit as x approaches+x of (x^2-1)/(x-1) ?
The limit as x approaches+x of (x^2-1)/(x-1) is x+1