What is implicit (dy)/(dx),3e^{xy}-x=0 ?

The answer to implicit (dy)/(dx),3e^{xy}-x=0 is (dy)/(dx)=(1-3e^{xy}y)/(3e^{xy)x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

implicit (dy)/(dx),3e^{xy}-x=0

implicit derivative

\frac{d y}{d x}, 3 e^{x y} - x = 0

\frac{d y}{d x} = \frac{1 - 3 e ^{x y} y}{3 e ^{x y} x}

Solution steps

3 e^{x y} - x = 0

Treat

y

y (x)

Differentiate both sides:

3 e^{x y} (y + x \frac{d y}{d x}) - 1 = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{1 - 3 e ^{x y} y}{3 e ^{x y} x}

\frac{d y}{d x} = \frac{1 - 3 e ^{x y} y}{3 e ^{x y} x}

\int z^{2} d z

\frac{\partial}{\partial t} ((x - c t)^{4} + (x + c t)^{4})

\int \frac{( 4 x + 2 )}{x ^{3} - x ^{2} + 2 x} d x

y^{^{'}} = 2 t y^{2}

\frac{e ^{- s}}{( s + 1 ) ^{2}}

What is implicit (dy)/(dx),3e^{xy}-x=0 ?
The answer to implicit (dy)/(dx),3e^{xy}-x=0 is (dy)/(dx)=(1-3e^{xy}y)/(3e^{xy)x}